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(-1)=-x^2-9x+3
We move all terms to the left:
(-1)-(-x^2-9x+3)=0
We add all the numbers together, and all the variables
-(-x^2-9x+3)-1=0
We get rid of parentheses
x^2+9x-3-1=0
We add all the numbers together, and all the variables
x^2+9x-4=0
a = 1; b = 9; c = -4;
Δ = b2-4ac
Δ = 92-4·1·(-4)
Δ = 97
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-\sqrt{97}}{2*1}=\frac{-9-\sqrt{97}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+\sqrt{97}}{2*1}=\frac{-9+\sqrt{97}}{2} $
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